0=19x^2-20

Solution for 0=19x^2-20 equation:

0=19x^2-20

We move all terms to the left:

0-(19x^2-20)=0

We add all the numbers together, and all the variables

-(19x^2-20)=0

We get rid of parentheses

-19x^2+20=0

a = -19; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·(-19)·20
Δ = 1520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1520}=\sqrt{16*95}=\sqrt{16}*\sqrt{95}=4\sqrt{95}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{95}}{2*-19}=\frac{0-4\sqrt{95}}{-38}
=-\frac{4\sqrt{95}}{-38}
=-\frac{2\sqrt{95}}{-19}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{95}}{2*-19}=\frac{0+4\sqrt{95}}{-38}
=\frac{4\sqrt{95}}{-38}
=\frac{2\sqrt{95}}{-19}
$